Erste Schritte Sort in java

[Tw1Z]

Helo, im new to java and want to ask a question. My task is to make a massive and then sort 0 column of this massive, how should i change my code?

import java.util.Arrays;

public class ClassTask {

    public static void main(String[] args) {

        int n = 4; // rows

        int m = 56; // columns

        int a = 0; // min

        int b = 6; // max

        int[][] mas = new int[n][m];

        for (int i = 0; i < mas.length; i++) {

            for (int j = 0; j < mas.length; j++) {

                mas[j] = (int)(Math.random() * (1 + b - a) + a);

                System.out.printf("%2d", mas[j]);

            }

            System.out.println();

            for (int i = 0; i < mas.length; i++) {

                Arrays.sort(mas);

                System.out.print(mas[0] + " ");

            }

        }

    }

}

 

[KonradN]

It seems that you added Code Tags after posting your code without them? Either some [i] were lost or your programm will not compile.

And please be aware: We do not like to guess! So please always provide details: What is exactly your problem? What happens? What do you expect?

My guess would be: Your output is just a bunch of "[I@....." (or something like that!) because that is the default way a reference is printed. So you have to use a methode to print the array - either write one yourself or use Arrays.toString to get a String with the content of an array.

 

[temi]

As a little hint by the side. Instead of commenting it, better use good names. Compare this:

int n = 4; // rows
int m = 56; // columns
int a = 0; // min
int b = 6; // max

// somewhere else
(int)(Math.random() * (1 + b - a) + a); // what was 'a'?

int rows = 4;
int columns = 56;
int min = 0;
int max = 6;

// somewhere else
(int)(Math.random() * (1 + max - min) + max);